Java – accessing WSDL on Tomcat

I have a web service and I'm deploying it on GlassFish I passed http://localhost:10697/APIService/APIServiceService?wsdl Accessed its WSDL

Now I will migrate the war file to Tomcat 6.0 24, and deploy it But I tried to access its WSDL usage http://localhost:8080/APIService/APIServiceService?wsdl , but I received 404 errors I tried various combinations, but it didn't seem to work

How do I access the WSDL file plz?

Thank you and salute,

Update: Here you are: Web xml：

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
    <session-config>
        <session-timeout>
            30
        </session-timeout>
    </session-config>
    <welcome-file-list>
        <welcome-file>index.jsp</welcome-file>
    </welcome-file-list>
</web-app>

I can't find sun jaxws However... Thank you very much! to greet

Solution

The way WSDL is accessed is not container - specific WS - stack Ws stack in GlassFish is Metro (Metro = jax-ws RI WSIT) Do you install / deploy Metro or jax-ws RI on Tomcat? For steps, see Metro on Tomcat 6 Jax or running jax-ws samples with Tomcat 6 X (jax-ws RI may be sufficient in your case)

Update: you need to be on the web Declare wsservlet in XML (see deploying Metro endpoint):

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
  <listener>
    <listener-class>
    com.sun.xml.ws.transport.http.servlet.WSservletcontextlistener
    </listener-class>
  </listener>
  <servlet>
    <servlet-name>WebServicePort</servlet-name>
    <servlet-class>
    com.sun.xml.ws.transport.http.servlet.WSServlet
    </servlet-class>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>WebServicePort</servlet-name>
    <url-pattern>/services/*</url-pattern>
  </servlet-mapping>
  <session-config>
    <session-timeout>60</session-timeout>
  </session-config>
</web-app>

Then in sun jaxws XML (also wrapped in WEB-INF), declare your service endpoint interface (SEI):

<?xml version="1.0" encoding="UTF-8"?>
<endpoints xmlns="http://java.sun.com/xml/ns/jax-ws/ri/runtime" version="2.0">
  <endpoint
  name="MyHello"
  implementation="hello.HelloImpl"
  url-pattern="/hello"
  />
</endpoints>

And you can access the WSDL:

http://localhost:8080/<mycontext>/services/hello?wsdl
           A               B         C       D

>A is the host and port of the servlet container. > B is the name of the war document. > C from the web URL pattern element in XML file. > D from sun jaxws The end of the URL - pattern attribute in the XML file