Java – the best string technology equals comparison

• Java

If the block is better?

private static void checkStr(String str) {

    if (str.equals("exit")) {
        System.out.println("It is equal");
    }
    if ("exit".equals(str)) {
        System.out.println("It is equal");
    }
}

Solution

Using the first method, you can provide margin for nullpointerexceptions So from my point of view, the second one is better

In the case of constants, you should prefer the second method to the first

"exit".equals(str)

You can find a detailed explanation here

I personally prefer another method Apache Commons – commons Lang has objectutils equals(Object,Object). Using this method, it is always safe even if null values are used

From documentation:

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