How to compare two string arrays without Java utils

Check whether array Arr1 contains the same elements as arr2 in the same order in Java

For example:

isTheSame({"1","2","3"},{"1","3"}) → true
    isTheSame({"1",{"2","1","1"}) → false
    isTheSame({"1",{"3","2"}) → false

So far I have

public boolean isTheSame(String[] arr1,String[] arr2)
{
   if (arr1.length == arr2.length)
   {
      for (int i = 0; i < arr1.length; i++)
       {
          if (arr1[i] == arr2[i])
          {
            return true;
          }
       }
    }
    return false;  
 }

The problem is that it only compares the first element of two arrays

Solution

You are iterating until you find a match You should look for a mismatched string. You should use equals not==

// same as Arrays.equals()
public boolean isTheSame(String[] arr1,String[] arr2) {
    if (arr1.length != arr2.length) return false;
    for (int i = 0; i < arr1.length; i++)
        if (!arr1[i].equals(arr2[i]))
            return false;
    return true;
}

FYI, this is arrays What equals does when dealing with null values

public static boolean equals(Object[] a,Object[] a2) {
    if (a==a2)
        return true;
    if (a==null || a2==null)
        return false;

    int length = a.length;
    if (a2.length != length)
        return false;

    for (int i=0; i<length; i++) {
        Object o1 = a[i];
        Object o2 = a2[i];
        if (!(o1==null ? o2==null : o1.equals(o2)))
            return false;
    }

    return true;
}