Java – string contains at least one number

I try to see if the string contains at least one number, either lowercase or uppercase

I wrote this:

int combinations = 0;
      string pass = "!!!AAabas1";

      if (pass.matches("[0-9]")) {
          combinations = combinations + 10;
      }

      if (pass.matches("[a-z]")) {
          combinations =combinations + 26;
      }

      if (pass.matches("[A-Z]")) {
          combinations =combinations + 26;
      }

But I don't understand why I can't get the combination to 36 They just kept it at 0 What did I do wrong?

Solution

You can use pattern. I think the "matches" method looks up the entire string to match the regular expression

Try the next code:

int combinations = 0;
    String pass = "!!AAabas1";
    if (Pattern.compile("[0-9]").matcher(pass).find()) {
        combinations = combinations + 10;
    }

    if (Pattern.compile("[a-z]").matcher(pass).find()) {
        combinations = combinations + 26;
    }

    if (Pattern.compile("[A-Z]").matcher(pass).find()) {
        combinations = combinations + 26;
    }