java. sql. Timestamp comparison error?

See English answer > java sql. Timestamp created from java. util. Date,why always before() it? two

Date d1 = new java.sql.Timestamp(new Date().getTime());
Thread.sleep(10);
Date d2 = new java.sql.Timestamp(new Date().getTime());
System.out.println("Date1: " + d1);
System.out.println("Date2: " + d2);
System.out.println("Comparing times d1.t < d2.t: " + (d1.getTime() < d2.getTime()));
System.out.println("Comparing dates d1.before(d2): " + (d1.before(d2)));

The output is as follows:

Date1: 2013-03-26 11:04:01.093
Date2: 2013-03-26 11:04:01.103
Comparing times d1.t < d2.t: true
Comparing dates d1.before(d2): false

This Java sql. What happened to the timestamp class?

Yes, I see this:

But its date is < - > time

In my example, I only have time stamps, and the behavior is unexpected

Update: answer

The reason for this is that the before () method is overloaded and will not be used in Java sql. Overridden in timestamp I look forward to "transcendence" behavior The correct way to compare timestamps is to use the timestamp variable instead of the date

This is still a bad design decision in the Java core, because inheritance should mean that timestamp is a date without penalties and exceptions

Solution

Try using timestamp instead of date, it will work

Timestamp d1 = new java.sql.Timestamp(new Date().getTime());

Timestamps and dates have their own methods of execution Verify