Java – why is there no exception in this byte?

I initialized a byte as follows:

byte b = (byte) 0b11110000000;

Since a byte is 8 bits in size, I expect it to throw some exceptions or errors, because this number should only be allocated to short or above It is also evaluated as - 124? Or could this be "normal" behavior? (no exception thrown, but variable overflow)?

Solution

You deserve - 128

When you explicitly convert int to byte, the lowest 8 bits will be obtained and the rest will be discarded

In your example, the lowest 8 bits are 10000000, and the decimal value of this number is - 128

Without explicit cast, the code will not compile because your assignment will result in information loss