“(? Pattern)” pattern is supported in Java

See English answers > regex named groups in java6

var pattern = @";(?<foo>\d{6});(?<bar>\d{6});";
var regex = new Regex(pattern,RegexOptions.None);
var match = regex.Match(";123456;123456;");

var foo = match.Groups["foo"].Success ? match.Groups["foo"].Value : null;
var bar = match.Groups["bar"].Success ? match.Groups["bar"].Value : null;

This seems to be a clean way to catch the group Can java do similar things, or do you need to grab groups according to the index location?

String foo = matcher.group(0);

Solution

This is supported from Java 7 Your c# code can be translated as follows:

String pattern = ";(?<foo>\\d{6});(?<bar>\\d{6});";
Pattern regex = Pattern.compile(pattern);
Matcher matcher = regex.matcher(";123456;123456;");
boolean success = matcher.find();

String foo = success ? matcher.group("foo") : null;
String bar = success ? matcher.group("bar") : null;

You must create a matcher object until you call find () to actually perform regular expression testing

(I use find () because it can find a match anywhere in the input string, such as regex Match() method If the regular expression matches the entire input string, then The matches () method returns only true)