Java regular expression content between single quotes

I try to write a regular expression in Java to find the contents between single quotes Can someone help me? I've tried the following, but it doesn't work in some cases:

Pattern p = Pattern.compile("'([^']*)'");

>Test case: 'Tumblr' is an amazing application expected output: Tumblr > test case: Tumblr is an amazing "application" expected output: Application > test case: Tumblr is an "amazing" application expected output: Amazing > test case: Tumblr is "great" and "amazing" expected output: great, Amazing > test case: users of Tumblr are disappointed. Expected output: none > test case: Tumblr's "acquisition" is completed, but users' loyalty doubts the expected output: acquisition

I appreciate any help

thank you.

Solution

This should be the trick:

(?:^|\s)'([^']*?)'(?:$|\s)

Example: http://www.regex101.com/r/hG5eE1

Java (ideone) year:

import java.util.*;
import java.lang.*;
import java.util.regex.*;

class Main {

        static final String[] testcases = new String[] {
            "'Tumblr' is an amazing app","Tumblr is an amazing 'app'","Tumblr is an 'amazing' app","Tumblr is 'awesome' and 'amazing' ","Tumblr's users' are disappointed ","Tumblr's 'acquisition' complete but users' loyalty doubtful"
        };

    public static void main (String[] args) throws java.lang.Exception {
        Pattern p = Pattern.compile("(?:^|\\s)'([^']*?)'(?:$|\\s)",Pattern.MULTILINE);
        for (String arg : testcases) {
            System.out.print("Input: "+arg+" -> Matches: ");
            Matcher m = p.matcher(arg);
            if (m.find()) {
                System.out.print(m.group());
                while (m.find()) System.out.print(","+m.group());
                System.out.println();
            } else {
                System.out.println("NONE");
            }
        } 
    }
}