Java try catch statement

try {
    逻辑代码块1;
} catch(ExceptionType e) {
    处理代码块1;
}

Example 1

import java.util.Scanner;

public class Test02 {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(system.in);
        System.out.println("---------学生信息录入---------------");
        String name = ""; // 获取学生姓名
        int age = 0; // 获取学生年龄
        String sex = ""; // 获取学生性别
        try {
            System.out.println("请输入学生姓名：");
            name = scanner.next();
            System.out.println("请输入学生年龄：");
            age = scanner.nextInt();
            System.out.println("请输入学生性别：");
            sex = scanner.next();
        } catch (Exception e) {
            e.printStackTrace();
            System.out.println("输入有误！");
        }
        System.out.println("姓名：" + name);
        System.out.println("年龄：" + age);
    }
}

---------学生信息录入---------------
请输入学生姓名：
徐白
请输入学生年龄：
110a
java.util.InputMismatchException
    at java.util.Scanner.throwFor(UnkNown Source)
    at java.util.Scanner.next(UnkNown Source)
    at java.util.Scanner.nextInt(UnkNown Source)
    at java.util.Scanner.nextInt(UnkNown Source)
输入有误！
姓名：徐白
年龄：0
    at text.text.main(text.java:19)