Java – position in the lower right corner of the screen
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Java
I need to put JFrame on the screen But I can't make them appear on the right side at the bottom of the screen
Please have someone explain how I locate them. It would be great if you could describe how to do it
This is the code so far
//Gets the screen size and positions the frame left bottom of the screen
GraphicsEnvironment ge = GraphicsEnvironment.getLocalGraphicsEnvironment();
GraphicsDevice defaultScreen = ge.getDefaultScreenDevice();
Rectangle rect = defaultScreen.getDefaultConfiguration().getBounds();
int x = (int)rect.getMinX();
int y = (int)rect.getMaxY()- frame.getHeight();
frame.setLocation(x,y - 45);
Solution
Try the following example Note 07000 "how to resize this window to fit the preferred size and layout of its subcomponents."
import java.awt.Dimension;
import java.awt.EventQueue;
import java.awt.GraphicsDevice;
import java.awt.GraphicsEnvironment;
import java.awt.Rectangle;
import javax.swing.JFrame;
import javax.swing.JPanel;
/** @see https://stackoverflow.com/q/9753722/230513 */
public class LowerRightFrame {
private void display() {
JFrame f = new JFrame("LowerRightFrame");
f.add(new JPanel() {
@Override // placeholder for actual content
public Dimension getPreferredSize() {
return new Dimension(320,240);
}
});
f.pack();
f.setDefaultCloSEOperation(JFrame.EXIT_ON_CLOSE);
GraphicsEnvironment ge = GraphicsEnvironment.getLocalGraphicsEnvironment();
GraphicsDevice defaultScreen = ge.getDefaultScreenDevice();
Rectangle rect = defaultScreen.getDefaultConfiguration().getBounds();
int x = (int) rect.getMaxX() - f.getWidth();
int y = (int) rect.getMaxY() - f.getHeight();
f.setLocation(x,y);
f.setVisible(true);
}
public static void main(String[] args) {
EventQueue.invokelater(new Runnable() {
@Override
public void run() {
new LowerRightFrame().display();
}
});
}
}
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