Java – how to append two bytes to int

I tried to append two bytes with hexadecimal values and store them as integers Obviously, everything is an unsigned value

Two bytes 0x20 0x07

Integer editor: Oh, I made a big mistake here Sorry for all the confusion I want to store integers 2007 instead of 0x2007 I'm really sorry

Is there any way to do this without converting bytes to string, appending and switching to int? Or is converting to string the only way?

Solution

You can try

byte b1 = (byte) 0x90;
byte b2 = (byte) 0xF7;

int i = ((b1 & 0xFF) << 8) | (b2 & 0xFF);

However, if you are using datainputstream or bytebuffers, you usually do not need to do so In both cases, you can use getshort