About vector / vector behavior in Julia

Given by 3 / [2; 2]

1×2 LinearAlgebra.Transpose{Float64,Array{Float64,1}}:
 0.75  0.75

And 3/ [2; 2] gives

2-element Array{Float64,1}:
 1.5
 1.5

The second one is easy to understand It broadcasts 3 and performs element wise partitioning But what is the reason behind the behavior of the first operation? I assume that it takes the sum of vectors, that is, 2 × 1. Execute 3 × Divide 4 and broadcast it to 1 × 2 transpose vector I can accept dividing the sum of vectors, but why transpose? Or why not return a scalar?

Solution

It just gives the pseudo inverse of the right operand

julia> ?/
...  
Right division operator: multiplication of x by the inverse of y on the right.

Although love at first sight seems surprising, it is actually a natural act Rowvector * columnvector gives a scalar, so scalar divided by column vector should give a row vector, which is the case Please note that rowvector has been deleted in 1.0. What you get is actually the row vector represented by transfer

You can write @ less 1 / [2; 2] to see what actually happens

In addition, please take a look at this GitHub issue to understand the behavior of some use cases and this discover topic