Java 8: find the index of the minimum value from the list

Say I have a list of elements (34,11,98,56,43)

Using the Java 8 stream, how do I find the index of the smallest element of the list (1 in this case)?

I know you can use list in Java Indexof (collections. Min (list)) is easily completed However, I'm looking at a solution like Scala. We can simply say list (34,43) zipWithIndex. min._ 2 to get the index of the minimum value

Is there anything that can use streams or lambda expressions (such as specific features of Java 8) to achieve the same results

Note: This is only for learning purposes I have no problems using the collections utility method

Solution

import static java.util.Comparator.comparingInt;

import static java.util.Comparator.comparingInt;

int minIndex = IntStream.range(0,list.size()).@R_516_2419@ed()
            .min(comparingInt(list::get))
            .get();  // or throw if empty list

As @ tagirvaleev mentioned in his answer, you can avoid boxing by using intstream #reduce instead of stream #min, but at the expense of concealing your intention:

int minIdx = IntStream.range(0,list.size())
            .reduce((i,j) -> list.get(i) > list.get(j) ? j : i)
            .getAsInt();  // or throw