Java – multiple clicks of the same button

The idea is that the button can perform one action on the first click and different actions on the second click

button_food   = (Button) findViewById(R.id.foodicon_layout);
button_travel = (Button) findViewById(R.id.travelicon_layout);
button_fuel   = (Button) findViewById(R.id.fuelicon_layout);
button_fetch  = (Button) findViewById(R.id.fetchicon_layout);

button_travel.setOnClickListener(new View.OnClickListener() {
    public void onClick(View v) {

        // Perform action on click
        button_food.setVisibility(View.GONE);
        button_fuel.setVisibility(View.GONE);
        button_fetch.setVisibility(View.GONE);
    }
});

In the given example, click button_ When traveling, other buttons will become invisible Click the same button again and I want the other buttons to be visible again

Solution

You can set the visibility of the button by taking the current visibility and switching it

button_food   = (Button) findViewById(R.id.foodicon_layout);
button_travel = (Button) findViewById(R.id.travelicon_layout);
button_fuel   = (Button) findViewById(R.id.fuelicon_layout);
button_fetch  = (Button) findViewById(R.id.fetchicon_layout);

button_travel.setOnClickListener(new View.OnClickListener() {
    public void onClick(View v) {

        int visibility = button_food.getVisibility() == View.VISIBLE ? View.GONE : View.VISIBLE;

        // Perform action on click
        button_food.setVisibility(visibility);
        button_fuel.setVisibility(visibility);
        button_fetch.setVisibility(visibility);
    }
});

Writing it like this is just a simple way to write if statements

int visibility;
if(button_food.getVisibility() == View.VISIBLE){
     visibility = View.GONE;
} else {
     visibility = View.VISIBLE;
}