Java – try, catch and finally blocks

public class D {

public class D {

void myMethod() {
    try {
        throw new IllegalArgumentException();
    } catch (NullPointerException npex) {
        System.out.println("NullPointerException thrown ");
    } catch (Exception ex) {
        System.out.println("Exception thrown ");
    } finally {
        System.out.println("Done with exceptions ");
    }
    System.out.println("myMethod is done");
}

public static void main(String args[]) {
    D d = new D();
    d.myMethod();
}

}

I don't understand why "mymethod complete" is printed out An exception is thrown, so it assumes that a matching catch is found and the finally block is executed, but it continues on the mymethod method method and prints that the mymethod is completed, which is not part of the finally block Why?

Solution

This is how try catch finally works Because you caught an exception, it is considered handled and execution continues normally

If you don't catch it or throw it again, "mymethod is finished" won't be printed, and the exception will pop up in the stack until it is caught by others

Note that finally blocks are always executed, exception or no