How do I convert strings to operators in Java?
•
Java
See English answers > is it possible to pass arithmetic operators to a method in Java? 8
import java.io.*;
import java.math.*;
public class ReadString {
public static void main (String[] args) {
System.out.print("Enter the first number: ");
BufferedReader br = new BufferedReader(new InputStreamReader(system.in));
int numOne = 0 ;
int numTwo = 0 ;
String opOne = null;
while(true){
try {
numOne = Integer.valueOf(br.readLine());
break;
} catch (IOException error) {
System.out.println("error; try again.");
System.exit(1);
}
catch (NumberFormatException nfe) {
System.out.println("error;try again.");
}
}
System.out.print("Enter the second number: ");
while(true){
try {
numTwo = Integer.valueOf(br.readLine());
break;
} catch (IOException error2) {
System.out.println("error");
System.exit(1);
} catch (NumberFormatException nfe) {
System.out.println("error;try again.");
}
}
System.out.println("What would you like to do with " + numOne + " and " + numTwo + "?");
try {
operator = br.readLine();
} catch (IOException ioe) {
System.out.println("error");
System.exit(1);
} catch (NumberFormatException nfe) {
System.out.println("error");
}
}
}
Solution
The simplest way to do this is the sequence of if then else statements:
if ("+".equals(opOne)) {
res = numOne + numTwo;
} else if ("-".equals(opOne)) {
res = numOne - numTwo;
} ...
An advanced method is to define an interface for the operator and put the instance in the map container:
interface Operation {
int calculate(int a,int b);
}
static final Map<String,Operation> opByName = new HashMap<String,Operation>();
static {
opByName.put("+",new Operation() {
public int calculate(int a,int b) {
return a+b;
}
});
opByName.put("-",int b) {
return a-b;
}
});
opByName.put("*",int b) {
return a*b;
}
});
opByName.put("/",int b) {
return a/b;
}
});
}
Using this initialized map, you can perform the following calculations:
int res = opByName.get(opOne).calculate(numOne,numTwo);
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