. net – LinkedList. Contains. What is the method used to compare objects?

LinkedList. Contains method (.NET 2)

How to compare objects in it? (equal to "CompareTo")

MSDN knows nothing about it

situation:

interface IClass
{
    string GetName();
}

class Class1 : IClass,IEquatable<Class1>
{
    public string FirstName;
    public string LastName;

    string IClass.GetName() { return FirstName; }

    bool IEquatable<Class1>.Equals(Class1 other)
    {
        return FirstName.Equals(other.FirstName);
    }
}

class Class2 : IClass,IEquatable<Class2>
{
    public string FirstName;
    public string LastName;

    string IClass.GetName() { return LastName; }

    bool IEquatable<Class2>.Equals(Class2 other)
    {
        return LastName.Equals(other.LastName);
    }
}

public void TestMethod() 
{
    Class1 c1 = new Class1();
    c1.FirstName = "fn";
    c1.FirstName = "ln";

    Class2 c2 = new Class2();
    c2.FirstName = "fn";
    c2.FirstName = "ln";

    Class1 c3 = new Class1();
    c3.FirstName = "fn";
    c3.FirstName = "ln";

    LinkedList<IClass> myList = new LinkedList<IClass>();
    myList.AddFirst(c1);
    myList.AddFirst(c2);
    // false here
    Message@R_527_2419@.Show("myList<IClass> contains c3? - " + (myList.Contains(c3)));

    LinkedList<Class1> myList1 = new LinkedList<Class1>();
    myList1.AddFirst(c1);
    myList1.AddFirst(c1);
    // true here
    Message@R_527_2419@.Show("myList1<Class1> contains c3? - " + (myList1.Contains(c3)));
}

Solution

Since the linked list is not a dictionary, I want it to use equality comparer < T > Default. Equals(x,y).

This supports (in order):

>Iequatable < T > (for problematic T) > object Equals (reference equality is used by default, or overridden equals (object) is supported)

Note that equalitycomparer < T > also handles these two classes and the common null rules of nullable < T >

(update: check, correct; from find (T))

...
EqualityComparer<T> comparer = EqualityComparer<T>.Default;
...
if (comparer.Equals(head.item,value)) {...}
...

Update to prove this in isomeinterface: iequatable < isomeinterface & gt;, According to comments:

using System;
using System.Collections.Generic;


class Program
{
    static void Main()
    {
        LinkedList<IFoo> foos = new LinkedList<IFoo>();
        foos.AddLast(new Foo1("abc"));
        foos.AddLast(new Foo2("def"));
        Console.WriteLine("checking contains...");
        bool c = foos.Contains(new Foo1("ghi"));
        Console.WriteLine("...done");
    }
}
interface IFoo : IEquatable<IFoo>
{
    void Bar();
}
class Foo1 : IFoo
{
    public string Value { get; set; }
    public Foo1(string value) { Value = value; }
    public override bool Equals(object other)
    {
        Console.WriteLine(Value + " > override Equals");
        return base.Equals(other);
    }
    bool IEquatable<IFoo>.Equals(IFoo other)
    {
        Console.WriteLine(Value + " > explicit Equals");
        return base.Equals(other);
    }
    public void Bar() { }
    public override int GetHashCode() { return base.GetHashCode(); }
}
class Foo2 : IFoo
{
    public string Value { get; set; }
    public Foo2(string value) { Value = value; }
    public override bool Equals(object other)
    {
        Console.WriteLine(Value + " > override Equals");
        return base.Equals(other);
    }
    public bool Equals(IFoo other)
    {
        Console.WriteLine(Value + " > implicit Equals");
        return base.Equals(other);
    }
    public void Bar() { }
    public override int GetHashCode() { return base.GetHashCode(); }
}