Java recursive insertion sort?
•
Java
So I tried to turn the following code into a recursive method to insert sorting, but although I tried, I couldn't Who can help me?
public static void insertionSort(int[] array){
for (int i = 1; i < array.length; i++){
int j = i;
int B = array[i];
while ((j > 0) && (array[j-1] > B)){
array[j] = array[j-1];
j--;
}
array[j] = B;
}
}
Editor: I'm thinking about such a thing, but it doesn't seem very complicated to me
public static void insertionSort(int[] array,int index){
if(index < array.length){
int j = index;
int B = array[index];
while ((j > 0) && (array[j-1] > B)){
array[j] = array[j-1];
j--;
}
array[j] = B;
insertionSort(array,index + 1);
}
}
Solution
Try this:
public class RecursiveInsertionSort {
static int[] arr = {5,2,4,6,1,3};
int maxIndex = arr.length;
public static void main(String[] args) {
print(arr);
new RecursiveInsertionSort().sort(arr.length);
}
/*
The sorting function uses 'index' instead of 'copying the array' in each
recursive call to conserve memory and improve efficiency.
*/
private int sort(int maxIndex) {
if (maxIndex <= 1) {
// at this point maxIndex points to the second element in the array.
return maxIndex;
}
maxIndex = sort(maxIndex - 1); // recursive call
// save a copy of the value in variable 'key'.
// This value will be placed in the correct position
// after the while loop below ends.
int key = arr[maxIndex];
int i = maxIndex - 1;
// compare value in 'key' with all the elements in array
// that come before the element key.
while ((i >= 0) && (arr[i] > key)) {
arr[i+1] = arr[i];
i--;
}
arr[i+1] = key;
print(arr);
return maxIndex + 1;
}
// code to print the array on the console.
private static void print(int[] arr) {
System.out.println();
for (int i : arr) {
System.out.print(i + ",");
}
}
}
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