Java-8 – intersection of collection flows to new collections
•
Java
Is there a better and simpler way to solve this problem?
@Test
public void testReduce() {
Set<Integer> foo = ImmutableSet.of(1,2,3,4,8,9);
Set<Integer> bar = ImmutableSet.of(1,5,11);
//DO think about solution for 1..n sets,and not only two.
Set<Integer> intersection = ImmutableList.of(foo,bar)
.stream()
.reduce( null,(a,b) -> {
if ( a == null ) {
a = new HashSet<Integer>(b);
}
else {
a.retainAll(b);
}
return a;
});
assertThat( intersection,is( ImmutableSet.of( 1,8) ) );
}
Solution
Reduce is the wrong method because it is not allowed to modify the parameters of the function in this way This is a variable reduction, also known as collection:
List<Set<Integer>> listOfSets=…;
//check if at least one set is in the list
Set<Integer> intersection = listOfSets.stream().skip(1)
.collect(()->new HashSet<>(listOfSets.get(0)),Set::retainAll,Set::retainAll);
The first set must be viewed. This is a disadvantage, but using null as the identification value is not clean (and cannot be used with collect because the accumulator cannot return a new set)
The content of this article comes from the network collection of netizens. It is used as a learning reference. The copyright belongs to the original author.
THE END
二维码
