Java – how to generate an IP address range given the start and end IP addresses?

• Java

How do I generate a series of IP addresses from the start and end IP addresses?

Network example "192.168.0.0/24":

String start = "192.168.0.2"
String end = "192.168.0.254"

I hope to have:

192.168.0.2
192.168.0.3
192.168.0.4
192.168.0.5
...
192.168.0.254

PS: network, start and end IP can be dynamic. The above is just an example

Thank you

Solution

Recognize that each of the four components of the IPv4 address is a hexadecimal number between 00 and FF

If you change the start and end IP addresses to 32-bit unsigned integers, you can cycle from the lowest to the highest, and convert each value of the cycle back to the IP address format

The range in the example you give is c0a80002 to c0a800fe

This is a code link that converts between hexadecimal numbers and IPv4 addresses

http://technojeeves.com/joomla/index.php/free/58-convert-ip-address-to-number

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