Compare twice in Java more or less
Date date1= new java.util.Date();
Date date1= new java.util.Date(); java.sql.Date sqldob = new java.sql.Date(date1.getTime()); System.out.println("date" +sqldob); Time sqldob1 = new Time(date1.getTime()); System.out.println("User Time: " +sqldob1); String yourTime="09:30:00"; SimpleDateFormat ra = new SimpleDateFormat("HH:mm:ss"); Date yourDate = ra.parse(yourTime); Time sqlTime3 = new Time(yourDate.getTime()); System.out.println("your time"+sqlTime3); if(sqldob1.before(sqlTime3)){ sqldob1 = sqlTime3; System.out.println("inside loop"); }
In the above code, I compare the two time variables for equality, but it provides the same value of - 1 for all types of input
Solution
You need to use the date #before (date), date #after (date) and date #equals (date) methods for basic date comparison
For example:
Date d1 = new Date(); Date d2 = new Date(); if(d1.after(d2)){ // Do something } if(d1.before(d2)){ // Do something } if(d1.equals(d2)){ // Do something }
You can also use the date #compareto (date) method, but you need to interpret the output of the CompareTo method accordingly
As the document says:
In your case, you get - 1 because
> new SimpleDateFormat(“HHH:mm:ss”); It's wrong Should be the new simpledateformat ("HH: mm: SS"); > int compare = sqlTime3. compareTo(sqldob1); This sqltime3 only has time The date is an era date you haven't mentioned, so it always appears before today's new date ()
Your solution: – (I hope this will solve your problem)
java.util.Date date1= new java.util.Date(); Time sqldob1 = new Time(date1.getTime()); System.out.println("User Time: " +sqldob1); Calendar cal = Calendar.getInstance(); cal.set(Calendar.HOUR_OF_DAY,19); // Your hour cal.set(Calendar.MINUTE,30); // Your Mintue cal.set(Calendar.SECOND,00); // Your second Time sqlTime3 = new Time(cal.getTime().getTime()); System.out.println("your time: "+sqlTime3); if(sqldob1.before(sqlTime3)){ sqldob1 = sqlTime3; System.out.println("inside loop"); }