Java – how to sort strings so that values with additional information are displayed first?

I tried to sort the following string

1.0.0.0-00000000-00000
2.1.0.0
2.2.0.0
2.3.0.0-00000000-00000

I currently have these values in a string array

String[] arrays = {"1.0.0.0-00000000-00000","2.1.0.0","2.2.0.0","2.3.0.0-00000000-00000"};

I try to have an output. If there is no "–", the values reach the end of my array in sorted order I want to output the following:

1.0.0.0-00000000-00000
2.3.0.0-00000000-00000
2.1.0.0
2.2.0.0

I tried arrays Sort (array), but I'm not sure how to sort it?

import java.util.Arrays;
import java.util.Comparator;
import java.util.Collections;

public class HelloWorld{

     public static void main(String []args){

       String[] arrays = {"1.0.0.0-00000000-00000","2.3.0.0-00000000-00000"};
       String[] newArray = new String[arrays.length];

    class CustomComparator implements Comparator<String>
    {
        @Override
        public int compare(String a,String b)
        {
            if(a.contains("-") && !b.contains("-"))
                 return 1;
            else if(!a.contains("-") && b.contains("-"))
                 return -1;
            return a.compareTo(b);
        }
    }

    Arrays.sort(arrays,new CustomComparator());

       for(String array : arrays)
       {
            System.out.println(array);
       }

     }
}


Error:

$javac HelloWorld.java 2>&1

HelloWorld.java:25: error: no suitable method found for sort(String[],CustomComparator)
    Collections.sort(arrays,new CustomComparator());
               ^
    method Collections.<T#1>sort(List<T#1>,Comparator<? super T#1>) is not applicable
      (no instance(s) of type variable(s) T#1 exist so that argument type String[] conforms to formal parameter type List<T#1>)
    method Collections.<T#2>sort(List<T#2>) is not applicable
      (cannot instantiate from arguments because actual and formal argument lists differ in length)
  where T#1,T#2 are type-variables:
    T#1 extends Object declared in method <T#1>sort(List<T#1>,Comparator<? super T#1>)
    T#2 extends Comparable<? super T#2> declared in method <T#2>sort(List<T#2>)
1 error



    The method gave me an output of 
2.1.0.0 
2.2.0.0
1.0.0.0-00000000-00000 
2.3.0.0-00000000-00000 

as opposed to

1.0.0.0-00000000-00000
2.3.0.0-00000000-00000
2.1.0.0 
2.2.0.0

Solution

Use comparator

import java.util.Comparator;
    class CustomComparator implements Comparator<String> {
        @Override
        public int compare(String a,String b) {
            if(a.contains("-") && !b.contains("-"))
                 return 1;
            else if(!a.contains("-") && b.contains("-"))
                 return -1;
            return a.compareTo(b);
        }
    }
    Collections.sort(arrays,new CustomComparator());

Returning a negative value means B precedes a, while a positive value means a precedes B