The shortest representation of special lambda expressions in Java 8

I'm new to Java 8 and I'm messing up a little

Now I have tried the andthen method of the function interface consumer in Java 8:

public static void main(String[] args) {
    List<Integer> ints = new ArrayList<Integer>();
    for (int i = 0; i < 5; i++) {
        ints.add(i);
    }
    Consumer<Integer> cons1 = in -> System.out.println("--> " + in);
    ints.forEach(cons1.andThen(in -> System.out.println("-+---> " + in)));
}

It works! The output is:

--> 0
-+---> 0
--> 1
-+---> 1
--> 2
-+---> 2
--> 3
-+---> 3
--> 4
-+---> 4

Now, I ask myself if I can connect two consumers (using the andthen method) without creating my own object for the first consumer cons1?

Solution

Yes, but it will be more confusing than a straightforward approach

You can write

ints.forEach(
   ((Consumer<Integer>) in -> System.out.println("--> " + in))
       .andThen(in -> System.out.println("-+---> " + in)));

But it's much better to write

ints.forEach(in -> {
  System.out.println("--> " + in);
  System.out.println("-+---> " + in);
});