Java – how do I decide which bufferedimage image type to use?

The Java bufferedimage class has a long list of class variables called image types, which can be used as parameters of the bufferedimage constructor

However, the Java documentation provides a minimal explanation of the purpose of these image types and how it will affect the bufferedimage to be created

My question is:

>How does the image type affect the bufferedimage to be created? Does it control the number of bits used to store various colors (red, green, blue) and their transparency? > If we just want to create, which image type should we use

>Opaque Image > transparent image > translucent image

I have read the description in Java doc many times, but we don't know how to use it For example, this one:

Solution

Use the default type unless you have specific requirements, such as saving memory or calculations or a specific native pixel format_ INT_ ARGB, 8 bits per channel, 3 channels alpha

When using 8 bits per channel, skipping the alpha channel will not affect the total memory occupied by the image, because in any case, each pixel will be packaged as int, so 8 bits will be discarded

Basically, you have:

> TYPE_ INT_ ARGB, 4 bytes per pixel, with alpha channel > type_ INT_ ARGB_ Pre, 4 bytes per pixel, the same as before, but the color has been multiplied by the alpha value of the pixel to save calculation > type_ INT_ RGB, no alpha channel > type_ USHORT_ 555_ RGB and type_ USHORT_ 565_ RGB, 2 bytes per pixel, much less color. You don't need to use it unless you have a memory limit

Then there are all the same types of formats and switching channels (e.g. BGR instead of RGB) You should select the native of the platform to reduce conversion