Java – a method to speed up full count sorting

I had a problem at hackerrank

Due to timeout, my first attempt passed all test cases except the last one After failing to propose a more efficient algorithm, I improved the code by using string builder instead of directly connecting strings This results in running times ranging from 5 seconds to 3.5 seconds

My question is, is there any other way to improve runtime? thank you.

Here is my code

public class Solution {

    public static void main(String[] args) {
        Scanner scanner = new Scanner(system.in);

        int N = scanner.nextInt();
        scanner.nextLine();

        int[] oriNum = new int[N];        
        String[] oriStr = new String[N];
        int[] count = new int[100];
        int[] indices = new int[100];
        int[] output = new int[N];

        // save the originals and the count array
        for (int i = 0; i < N; i++) {
            oriNum[i] = scanner.nextInt();
            oriStr[i] = scanner.nextLine().trim();
            count[oriNum[i]]++;
        }

        // accumulate the count array
        indices[0] = 0;
        for (int i = 1; i < 100; i++) {
            indices[i] = indices[i-1] + count[i-1];
        }

        // output order
        for (int i = 0; i < N; i++) {
            int num = oriNum[i];
            output[indices[num]++] = i;
        }

        int bar = N/2;
        StringBuilder sb = new StringBuilder();
        for (int i = 0; i < N; i++) {            
            int index = output[i];
            if (index < bar) 
                sb.append("- ");
            else 
                sb.append(oriStr[index]+ " ");
        }
        System.out.println(sb.toString());
    }
}

Solution

You should try using a normal buffer reader instead of a scanner The speed of the scanner is very slow. I participated in the programming competition, in which scanner is the only reason for "exceeding the time limit"

The content of this article comes from the network collection of netizens. It is used as a learning reference. The copyright belongs to the original author.
THE END
分享
二维码
< <上一篇
下一篇>>