Java reads hexadecimal values into arrays of type int
                                        
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                    Java                                    
                I have a file that contains integers in hexadecimal
I know you can say int i = 0x
But when reading I get the wrong value, I can't do this?
Thank you in advance!
Solution
You may want to pass integer parseInt(yourHexValue,16).
Example:
// Your reader
BufferedReader sr = new BufferedReader(new StringReader("cafe\nBABE"));
// Fill your int-array
String hexString1 = sr.readLine();
String hexString2 = sr.readLine();
int[] intArray = new int[2];
intArray[0] = Integer.parseInt(hexString1,16);
intArray[1] = Integer.parseInt(hexString2,16);
// Print result (in dec and hex)
System.out.println(intArray[0] + " = " + Integer.toHexString(intArray[0]));
System.out.println(intArray[1] + " = " + Integer.toHexString(intArray[1]));
Output:
51966 = cafe 47806 = babe
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