Representing numbers in byte arrays (Java programming)

I tried to use a two byte array to represent port number 9876 (or 0x2694 in hexadecimal):

class foo {
     public static void main (String args[]) {
   byte[] sendData = new byte[1];

   sendData[0] = 0x26;
   sendData[1] = 0x94;
     }
}

But I got a warning about possible loss of accuracy:

foo.java:5: possible loss of precision
found   : int
required: byte
   sendData[1] = 0x94;
                 ^
1 error

How to represent the number 9876 in a two byte array without losing precision?

Note: I chose @ BJ ö RN's code as the correct answer, but @ glowcoder's code also works well This is just another way to solve the same problem Thank you!

Solution

My first answer is bit shifting, but in my second idea, I think using output stream may be better and easier to understand I usually avoid casting spells, but if you're not going to use a general solution, I think it's OK

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