Java 8 stream – merge two sets to make them unique in a specific field [copy]
•
Java
See English answers > java 8 distinct by property 20
This is the best I can do in Java, but it collects unique names instead of dogs: (dogs contain fields other than names)
// collect all dogs names from first list
List<String> dogNames1 = dogsList1.stream()
.map(x -> x.getName()).collect(Collectors.toList());
dogList2.stream()
.filter(x->!dogNames1.contains(x.getName()))
.forEach( x->
dogsList1.add(x);
);
Can it be improved? There are other better solutions or optimization methods
Solution
You can use to merge multiple streams and delete duplicates
For the first dog with a given name, you can do it
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.stream.Collectors;
import java.util.stream.Stream;
public class A {
public static void main(String[] args) {
List<Dog> dogList1 = Arrays.asList(new Dog("a",1),new Dog("b",2),new Dog("f",3));
List<Dog> dogList2 = Arrays.asList(new Dog("b",4),new Dog("c",5),6));
List<Dog> dogList3 = Arrays.asList(new Dog("b",7),new Dog("d",8),new Dog("e",9));
List<Dog> dogs = new ArrayList<>(
Stream.of(dogList1,dogList2,dogList3)
.flatMap(List::stream)
.collect(Collectors.toMap(Dog::getName,d -> d,(Dog x,Dog y) -> x == null ? y : x))
.values());
dogs.forEach(System.out::println);
}
}
class Dog {
String name;
int id;
public Dog(String name,int id) {
this.name = name;
this.id = id;
}
public String getName() {
return name;
}
@Override
public String toString() {
return "Dog{" +
"name='" + name + '\'' +
",id=" + id +
'}';
}
}
Dog{name='a',id=1}
Dog{name='b',id=2}
Dog{name='c',id=5}
Dog{name='d',id=8}
Dog{name='e',id=9}
Dog{name='f',id=3}
In each case, you can see the first instance of the reserved name
For unique names
Set<String> names = Stream.of(dogList1,dogList3)
.flatMap(List::stream)
.map(Dog::getName)
.collect(Collectors.toSet());
The content of this article comes from the network collection of netizens. It is used as a learning reference. The copyright belongs to the original author.
THE END
二维码
