java – Integer. parseInt(“9999999990”);

See English answers > unexpected numberformatexception while parsing a hex string to an int value 5

String str="9999999990";
  int f = Integer.parseInt("2147483647");// No Exception here
        int x =Integer.parseInt(str);   // Exception is thrown here

Solution

Integer. When parsing that it cannot be expressed as int ParseInt will throw an exception The first example is nearly 10 billion, which is greater than the maximum possible int, which is slightly higher than 2 billion

Integer. ParseInt (string) delegates to integer ParseInt (string, 10), that is, the version with cardinality, and the JavaDocs status:

(emphasize my)

If you need to parse it, you can use long Parselong, which will handle larger numbers